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April 19, 2024, 11:41:54 am

Author Topic: What is ln[x]?  (Read 1480 times)  Share 

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suskieanna

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What is ln[x]?
« on: December 27, 2018, 10:32:09 am »
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Hello I am trying plot a graph of and I don't know what ln
  • is. Is it just log graph?

RuiAce

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Re: What is ln[x]?
« Reply #1 on: December 27, 2018, 10:35:13 am »
+5
\( \ln x\) is just a shorthand for \( \log_e x\) if that was your question. (So what you have there is basically the reciprocal of a log graph, yes.)
« Last Edit: December 27, 2018, 10:39:43 am by RuiAce »

Tatlidil

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Re: What is ln[x]?
« Reply #2 on: January 15, 2019, 09:31:41 pm »
+1
\( \ln x\) is just a shorthand for \( \log_e x\) if that was your question. (So what you have there is basically the reciprocal of a log graph, yes.)
So if that is the reciprocal, how do you find the inverse of that?
And I just wanted to know if i'm correct with this:
The reciprocal of y = sin(x) is cosec(x)
The inverse of y = sin(x) is sin^-1(x) or arcsine(x)?
P.S I'm just a little confused with sketching these as well, lets say x: [0 , pi/2]

« Last Edit: January 16, 2019, 11:20:33 am by Tatlidil »

DBA-144

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Re: What is ln[x]?
« Reply #3 on: January 15, 2019, 10:07:47 pm »
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So if that is the reciprocal, how do you find the inverse of that?
And I just wanted to know if i'm correct with this:
The reciprocal of y = sin(x) is cosec(x)
The inverse of y = sin(x) is sin^-1(x) or arcsine(x)?
P.S I'm just a little confused with sketching these as well, lets say x: [0 , 2pi]


Pretty sure you cant sketch inverse trig functions for the domain youve said since they re not one to one functions
 It would need to be 0 to pi/2 for sin and i think 0 to pi for cos. 

Hope this helps.
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Tatlidil

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Re: What is ln[x]?
« Reply #4 on: January 16, 2019, 11:17:48 am »
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Pretty sure you cant sketch inverse trig functions for the domain youve said since they re not one to one functions
 It would need to be 0 to pi/2 for sin and i think 0 to pi for cos. 

Hope this helps.
Oh yeah i forgot, it has to be a one-to-one function I'll change it now.