This is what I got
I think it may be wrong
(Image removed from quote.)
You didn't understand what Jake said.
Think about what the derivative is. If the derivative f'(x) is negative (below the x-axis), then the original function f(x) is DECREASING.
If the derivative is positive (above the x-axis), then the original function f(x) is INCREASING.
If the derivative is 0 (x-intercept), then the original function has a STATIONARY POINT.
(Also it doesn't matter where your graphs start. They can start however low and however high you like. All we care about is that your curve's stationary points are placed at a correct x-coordinate and it increases/decreases where it should be.)
As an exercise, you may wish to sketch y=4x2(x-3) and an antiderivative y=x3(x-4). Use GeoGebra or just Desmos to ensure your graph is correct.
Compare where the DERIVATIVE is ABOVE the x-axis, to where the ORIGINAL CURVE is INCREASING.