Actually, any form of increasing/decreasing would include the turning point as an endpoint. Unless your function is actually constant at the turning point (what I mean is something like:
y = (x-2)^3 x>2
0 for |x|<=2
(x+2)^3 for x<-2; here, the function is actually constant for |x|<=2)
This is because the definition of increasing simply says:
If b>a, then f(b) > =f(a)
Even at one end of a turning point, the function still changes. Consider y = x^2. It is increasing on the interval [0, infinity) because on this interval, if you choose ANY b and a such that b>a, then f(b) >= f(a).
The difference between strictly increasing and increasing is that the set of increasing functions includes that weird example I gave above; that function is increasing on x >=-2, but strictly increasing on x>=2 only. Strictly increasing requires if b>a, f(b) > f(a), i.e. a strict inequality.