Can anyone help me out with part ei and eii? I've read the examiners report and don't understand it
Thanks in advance!
You have two chromosomes we are dealing (1 and 2) with: BOTH REPLICATE so visually it looks like
XX ( chromosome 1) and XX ( chromosome 2)
Now the two sister chromatids will cross over which results in recombinant DNA!
So for chromosome 1: The chromatids have a different combination of alleles now!
2 are normal whilst 2 are recombined
Now the same thing happens with chromosome 2
2 are normal whilst 2 are recombined
So we want the chance a sperm cell has both a normal 2 and a normal 1 chromosome
There is 0.5 chance of getting a normal 1 chromosome and 0.5 chance of getting a normla 2 chromosome
HENCE 0.5 X 0.5 = 0.25
AKA 1/4
idk if that is correct but that is how i would figure it out